If the roots of the given quadratic equation are real and equal then find the value of ‘m’.

(m-12) x2 + 2 (m-12) x + 2 = 0​

m = (12 x^2 + 24 x - 2)/(x^2 + 2 x)

Step-by-step explanation:

Solve for m:

2 + 2 x (m - 12) + x^2 (m - 12) = 0

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand and collect in terms of m:

2 - 24 x - 12 x^2 + m (x^2 + 2 x) = 0

Hint: | Isolate terms with m to the left hand side.

Subtract -12 x^2 - 24 x + 2 from both sides:

m (x^2 + 2 x) = 12 x^2 + 24 x - 2

Hint: | Solve for m.

Divide both sides by x^2 + 2 x:

m = (12 x^2 + 24 x - 2)/(x^2 + 2 x)

she drove 134 miles

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v