Solve By Substitution: (With explanation Please!)

-5x + y = -3
3x - 8y = 24

-5x + y = -3A

3x - 8y = 24...B

Solve A for y.

-5x + y = -3

y = 5x - 3

Plug into B to solve for x

3x - 8(5x-3) = 24

3x -40x + 24 = 24

-37x = 24 - 24

-37x = 0

x = 0/-37

x = 0

Now that we know x, plug the value of x into A or B (your choice) to find y.

I will use B.

3x - 8y = 24

3(0) - 8y = 24

0 - 8y = 24

-8y = 24

y = 24/-8

y = -3

x = 0, y = -3

given:

-5x + y = -3

3x - 8y = 24

1st method

3x - 8y = 24

8y = 3x - 24

y = (3x - 24)/8

-5x + y = -3

-5x + (3x - 24)/8 = -3

(-40x + 3x - 24)/8 = -3

(-37x - 24)/8 = -3

(-37x - 24) = -3 × 8

-37x - 24 = -24

-37x = 24 - 24

-37x = 0

x = 0

2nd method

y - 5x = -3

y = 5x-3

3x - 8y = 24

3x - 8(5x-3) = 24

3x - 40x + 24 = 24

3x + 40x = 24 - 24

43x = 0

x = 0

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

here is your mark brainliest