Find the interquartile range (IQR) of the data in the dot plot below

2 cm

Step-by-step explanation:

As we know, the iqr is found by subtracting Q3-Q1. So that means we need to find them first. Finding the median will help us accomplish this task. So when writing out the numbers to solve it 81,82,83,83,84,84,84,85 because the amount of data points are an even number, we will have two data points which will help us solve our median which in this case is where the 83 and 84 meet. Our median is thus 83+84/2 which is 83.5. Now look on both sides of the two numbers which make up our median. On either side of the 2 data points needed for the median, the is another 3 data points. To find your q1 and q3, you need to find the median of these numbers. For Q1 look for the median between the numbers 81,82,83 and for Q3, look for the median in the numbers 84,84,85. So, knowing this information, our Q1 value is 82 and our Q3 value is 84. So input these into the equation we have up top which is Q3-Q1=IQR so 84-82=IQR, thus, our IQR is 2.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer:

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21  

-7 + ? = 21

-7 + 28 = 21

hope it