Sum of digits in a three digit number is nine. The tens digit is half sum of the other two and the hundreds digit is half the units digits. Find the number​

234

Step-by-step explanation:

Let the digit in the hundreds place be a, the digit in the tens place be b and the digit in the ones place be c. So a b c is the number.

(Based on the question) a + b + c = 9 Equation 1

From Equation 1, you can get:

2a + 2b + 2c = 18 Equation 2

(Based on the question) 2b = a + c Equation 3

(Based on the question) 2a = c Equation 4

Replace the c in Equation 3 with Equation 4:

2b = a + 2a

Evaluate.

2b = 3a Equation 5

Replace all the values of b and c with Equations 4 and 5 respectively into Equation 1 (Check underlined Equations to realise that all terms equal to a term in a):

2a + 3a + 2(2a) = 18

Evaluate.

2a + 3a + 4a = 18

9a = 18

Find a.

a = 18 ÷ 9

a = 2

Based on Equation 4, find c.

c = 2 × 2

c = 4

Based on Equation 1, find b.

b = 9 - 2 - 4

b = 3

Piecing together the values of a, b and c, the number is 234.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!