Suppose X is normally distributed with mean 20 and standard deviation 4, find the value x0 such that P(X ≥ x0) = 0.975.

12.16

Step-by-step explanation:

From your question, we have the following information

Mean = u = 20

Standard deviation sd = 4

P(X>Xo) = 0.975

1-0.975 = 0.025

P(z<Xo-20/4) = 0.025

Xo-20/4 = -1.96

We cross multiply

Xo - 20 = -1.96 x 4

Xo - 20 = -7.84

Xo = -7.84+30

Xo = 12.16

12.16 is the value of Xo and therefore the answer to this question.

Thank you!

b i think

step-by-step explanation:

not really sure