PLS HELP ASAP Use the Pythagorean identity, (x^2-y^2) + (2xy)^2 = (x^2+y^2)^2 , to create a Pythagorean triple.

Follow these steps:
1. Choose two numbers and identify which is replacing x and which is replacing y.

2. How did you know which number to use for x and for y?

3. Explain how to find a Pythagorean triple using those numbers.

4. Explain why at least one leg of the triangle that the Pythagorean triple represents must have an even-numbered length.

Number your responses from 1 to 4 so your instructor can tell which question you're responding to.

wfirfkfr/jjfi; jn; p/ojkfvlbvmkmgkgkkkgkkg

step-by-step explanation:

look at photo

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7