Help ASAP! 40 points plus !

Step-by-step explanation:

use the distance formula. calculate the distance between AB and then between CD showing AB = CD.

then use the distance formula on BC and AD, showing they are equal.

d=√((x_2-x_1)²+(y_2-y_1)²)

AD ≅ BC

DC ≅ DC

<A, <B, <C, <D

d=√((x_2-x_1)²+(y_2-y_1)²)

Step-by-step explanation:

There are a few ways to prove a quadrilateral is a rectangle. Here are three of the easiest ways: 1) Show all angles are 90°; 2) Show that one pair of sides is parallel and that two opposite angles are 90°; 3) Show the diagonals bisect each other and are of equal length.

The diagonals are congruent. Let's see why we can claim that the diagonals are congruent. Here is a sample proof: Given: Quadrilateral ABCD is a rectangle.

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.