Which equation is the inverse of y = 16x2 + 1? y=+
х
16
1
# VX-1
y =
16
I+
VE
--
4
4
#
X-1
4

Step-by-step explanation:

y = 16x^2 + 1,  We can divide both site of the equation to find the value of x.  You can do any valid operation on both sides of the equation and it will still be equal.

y - 1 = 16x^2     Divide both side by 16.

= x

The inverse is

(x) =

your answer is a

step-by-step explanation:

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37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3