In the given figure, AD, BE and CF are the medians of the ∆ABC, prove that vector AB +vector BE+vector CF=0​

Factor a^3 - 3 + 3a^2 - a. a) (a - 1)(a + 1)(a + 3) b) (a^2 + 1)(a - 3) c) (a^2 - 3)(a + 1

△cde maps to △stu with the transformations (x, y) arrowright (x − 2, y − 2) arrowright (3x, 3y) arrowright (x, −y). if cd = a + 1, de = 2a − 1, st = 2b + 3 and tu = b + 6, find the values of a and b. the value of a is and the value of b is .

Select all of the quadrants that the parabola whose equation is y=√x-4 (principal square root) occupies. i ii iii iv