What is the principal which would amount to $6900 in 3 years at 5% simple interest per annum?​

$6000

Step-by-step explanation:

accumulated amount = A = PI

A = $6900

Let P = x

6900 - I = x

I = (x)(0.05)(3yrs) = 0.15x

6900 - 0.15x = x

Add

6900 = 1.15x

Divide, solve for x

x = 6000

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

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