Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G(-2,3), H(4,4), J(2, -1), and K(-4, -2).

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

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step-by-step explanation: