You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Complete question :

You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Tiles : 7,6, 5, 8, 9, 10, 20

2 /7

Step-by-step explanation:

The probability of a compound event in the scenario described above :

P(1st pick) * p(second pick)

Recall: this event is without replacement

P(choosing two even numbers)

Probability = required outcome / Total possible outcomes

Required outcome = even Number tiles = (6, 8, 10, 20) = 4

Total possible outcomes = number of tiles = 7

P(even number on first pick) = 4/7

P(even on second pick) = 3 / 6 = 1/2

P(compound event) = 4/7 * 1 /2 = 4 /14 = 2 /7

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

yes

yes yes yes