Can I please have help with question 2) a and b

and

Step-by-step explanation:

(a)

A = × 4 ×

   = 2 ×

   = × ← rationalise the denominator

= units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4 )² + ( )²

    = 32 +

    = +

    = ( take the square root of both sides )

h = = × ← rationalise the denominator

h =

kjgfcvbjkl

step-by-step explanation:

sdfghjkl; vbnm,

126 maybe. sorry