PLEASE HELP On an algebra test, a total of 50 students had grades of B or C. There were 10 more students with C’s than B’s. Find the number of students who had a B and the number of students who had a C.

c

Step-by-step explanation:

Let the students with B(s) be x.

So, the students with C should 10 more than x = x + 10

Total students = 50

=> students with B + students with C = 50

=> x + (x + 10) = 50

=> 2x + 10 = 50

=> 2x = 50 - 10 = 40

=> x = 40/2 = 20

Thus,

students with B = x = 20

students with C = x + 10 = 20+10= 30

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

m

step-by-step explanation: