Does anyone know how to rewrite these into distributive property: b×(6+12)=
(3×a)+(3×b)=
5×(8+s)=
12×(s-10)=
(35×t)+(35×y)
​

false

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.