The height of a ball thrown straight up in the air is described using the equation h=12gt2+v0t+h0, where h=height
t=timeinseconds
g=accelerationduetogravity
v0=initialvelocity
h0=initialheight
The initial height is 2 meters above the ground, the initial velocity is 12.25 m/s2, and acceleration is the force of gravity near the Earth's surface, which is −9.8 m/s2.

(Acceleration is negative because it is downward relative to height.)

What is the tallest height the ball could reach?

Enter your answer as a number, rounded to the nearest tenth, with the appropriate unit, like this: 4.2 m

Hint: The highest or lowest point on any parabola (graph of a quadratic equation) is its vertex.