Find the slope of the line that passes through (4,7) and (1,10). Simplify your answer and write it as an improper fraction, proper fraction or an integer.

Step-by-step explanation:

co-ordinates = (4,7) and (1,10)

Slope = (y² -y¹) / (x² - x¹)

= (10-7) / (1-4)

= 3 / -3

= -1

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

14

step-by-step explanation:

14 x 3 = 42