A ball is thrown into the air with an initial velocity of 25 meters per second. The function h(t) = -4.9t2 + 25t + 6 represents the height of the ball above the ground in meters, with respect to time, t, in seconds. Part A: At h(3), then the height of the ball would be?
Part B: The graph below represents the height of the ball with respect to time.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

da freeck kinda math is this just drop out

step-by-step explanation:

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)