One grocery clerk can stock a shelf in 25 min. A second clerk requires 45 min to stock the same shelf. How long would it take to stock the shelf if the two clerks worked together?

Step-by-step explanation:

The rate of each clerk is 1/25 and 1/45 respectively so together they can stock the shelf

t/25+t/45=1 (the least common multiple of 25 and 45 is 225)

t/25(9/9)+t/45(5/5)=1

(9t+5t)/225=1

9t+5t=225

14t=225

t=225/14 min

t=16 minutes (rounded to nearest minute)

( or 16 minutes and about four seconds :) )

clerk A and clerk B can simultaneously stock a shelf in 180/13 minutes

Step-by-step explanation:

Let the first clerk be A and the second clerk be B

A can stock a shelf in 20 min

B can stock a shelf in 45 min

Consider the complete work to be W

A’s rate of stocking =  per minute

B’s rate of stocking =  per minute

When, A and B work simultaneously, rate of work done =

Total work done simulatenously =  180/13

Therefore, clerk A and clerk B can simultaneously stock a shelf in 180/13  minutes

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2