Simplify. Be sure to state the restrictions on the variables.
u+3/u^2−9

1/(u-3)

Step-by-step explanation:

(u+3)/(u^2-9)

(u+3)/[(u+3)(u-3)]

cancel out the (u+3)'s,

you get 1/(u-3).

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2