How many solutions does the system have? \begin{cases} 5x-y=2 5x-y=-2 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 5x−y=2 5x−y=−2 ​ Choose 1 Choose 1 (Choice A) A Exactly one solution (Choice B) B No solutions (Choice C) C Infinitely many solutions

The Answer is B, No Solutions

Step-by-step explanation

(Checked on khan) Basically think about it like this, if you were to substitute 1 for x and then 3 for y you would get 2, not -2. No Matter what you do or what you substitute you will never get -2 and 2 as an answer.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

sorry not sure

step-by-step explanation: