A school sold 51 less children’s tickets than adult tickets for the school play. Adult tickets cost $1.25 and children’s tickets cost $0.75. A total of $129.75 was taken in. How many of each kind were sold? Show work pls

84 adult tickets and 33 child tickets were sold.

Step-by-step explanation:

Given that a school sold 51 less children's tickets than adult tickets for the school play, and adult tickets cost $ 1.25 and children's tickets cost $ 0.75, and a total of $ 129.75 was taken in, to determine how many of each kind were sold the following calculations must be done:

61 x 1.25 + 10 x 0.75 = 83.75

81 x 1.25 + 30 x 0.75 = 123.75

82 x 1.25 + 31 x 0.75 = 125.75

83 x 1.25 + 32 x 0.75 = 127.75

84 x 1.25 + 33 x 0.75 = 129.75

Thus, 84 adult tickets and 33 child tickets were sold.

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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