F(x) = V22 g(x) = V322
Find (f .g)(x). Assume x2 0.
O A. (f. g)(x) = 8x
B. (f. g)(x) = 8VC
O c. (f. g)(x) = 32x
D. (f. g)(x) = V34x

Step-by-step explanation:

g(x) = √(32x) = √(2⁵x) = 4√(2x)

(f∘g)(x) = f(g(x))

= f(4√(2x))

= √(2 ⋅ 4√(2x))

= √(8√(2x))

= √8∜2∜x

= ∜(2⁷x)

= ∜(128x)

which doesn’t match any of the choices. There’s an error in the question.

I believe that the functions were written incorrectly and the x should not be part of the radicands (see attachment). That makes the answer A.

plants store their excess carbohydrate in the form of starch so that it could be used as energy source later on. the excess carbohydrate is converted into starch in the plastid i.e. chloroplast & this process occurs in the presence of sunlight. it is an insoluble polymer of glucose which gets stored in cell organelles named as amyloplasts. in some plants, starch is also stored in roots and embryos.

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah