Which of the following is equivalent to the addition problem below? 46.61 + 51.52
A.
(40 + 50) + (6 + 1) + (0.6 + 0.5) + (0.01 + 0.02)
B.
(40 + 50) + (6 + 5) + (0.6 + 0.1) + (0.01 + 0.02)
C.
(40 + 10) + (6 + 5) + (0.6 + 0.5) + (0.01 + 0.02)
D.
(40 + 50) + (6 + 1) + (0.6 + 0.1) + (0.05 + 0.02)

A) (40 + 50) + (6 + 1) + (0.6 + 0.5) + (0.01 + 0.02)

Step-by-step explanation:

In this case, you are breaking each term down to it's non-zero digits, and adding them:

46.61 = 40 + 6 + 0.6 + 0.01

51.52 = 50 + 1 + 0.5 + 0.02

Note however, that the answer choices add each individual non-zero terms together:

(40 + 50) + (6 + 1) + (0.6 + 0.5) + (0.01 + 0.02), or A)

A) (40 + 50) + (6 + 1) + (0.6 + 0.5) + (0.01 + 0.02) is your answer.

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answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead