Please PLEASE PLEASE

14, 21

Step-by-step explanation:

Let the two consecutive multiples be 7n and 7(n+1).

Now, it is given that:

(7n)² + [7(n+1)]² = 637

Simplifying,

49n² + (7n+7)² = 637

49n² + 49n² + 2(7n)(7) + 49 = 637

(as (x+y)² = x² + y² + 2xy)

98n² + 98n + 49 = 637

98n² + 98n - 588 = 0

Dividing by 98 to further simplify,

n² + n - 6 = 0

Factorising, we get

n² + 3n - 2n - 6 = 0

n(n+3) - 2(n+3) = 0

(n+3)(n-2) = 0

Therefore we get n = -3 or n = +2.

Hence, we get the consecutive multiples as 14 and 21.

Feel free to ask if you didn't understand any part.

Hope this helps! :D

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y