What is an equation for the line that passes through points (2.-3) and (1, 2)? (+ 3) = -5(x - 2) b. (y - 3) = 5(x ! 2) (y - 3) = -5(.x + 2) d. (+3) = S(x - 2)​

A. y + 3 = -5(x - 2)

Step-by-step explanation:

The slope is:

2 - (-3) / 1 - 2 = 5 / -1 = -5.

Then, put it in point slope form (which was where m is the slope, and (x1, y1) is the coordinate point it gives you. You can use m = -5, x1 = 2 and y1 = -3.)

y + 3 = -5(x - 2)

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3