Amotocross rider is in the air for 2.5 seconds. your camera can take a picture every 0.125 second. your friend's camera can take a picture every 0.15 second.

a. how much times faster is your camera than your friend's camera?

b. how many more pictures can you take while the rider is in the air?

a) Our camera is 1.2 times faster than friend's camera.

b) We can take 20 pictures while the rider is in the air.

Step-by-step explanation:

According to the given problem

a) 1 picture in our camera takes time =0.125 seconds

1 picture in friend's camera takes time =0.15 seconds

The rate of pictures taken by our camera=

The rate of pictures taken by friend's camera=

Now, scale factor by which our camera is faster then friend's camera=

Thus Our camera is 1.2 times faster than friend's camera.

b) Number of pictures we can take while the rider is in the air [∵Duration of motocross rider is in the air = 2.5 seconds.]

Thus we can take 20 pictures while the rider is in the air.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it