A rectangle has dimensions 8 1/5 in by 13 in. A diagonal of the rectangle forms two matching right triangles. What is the area of one of the triangles. The area of one of the triangle is _ in.

53.3 in^2

Step-by-step explanation:

Given data

Base B= 13in

Height H= 8 1/5 in= 41/5in

The expression for the area of a triangle is

Area= 1/2 Base * Height

Substitute

Area= 1/2* 13* 41/5

Area= 6.5*41/5

Area= 266.5/5

Area= 53.3 in^2

Hence the area is 53.3 in^2

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

54

step-by-step explanation: