I NEED HELP FOR ALL 4 OF THOSE! THAT’S IT! PLZ AND TY

Step-by-step explanation:

Given equation of a straight line is,

y = -4 - 2x

Domain of the line (x) → {-3, -2, -1, 0, 1}

Therefore, range for the given set of domain will be,

Range (y) → {2, 0, -2, -4, -6}

[By substituting the value of x in the given equation we get the value of y]

Set of scatter points are,

(-3, 2), (-2, 0), (-1, -2), (0, -4), (1, -6)

Now we plot these points to get the discrete graph as attached.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the square root of what number? if you add that, then someone will probably answer the question.