Find the equation of the line that contains the point (-4, -4) and is perpendicular to the line 4x+5y=5

Step-by-step explanation:

Given: A point  which is perpendicular to the line .

To find: The equation of the line which passes through and is perpendicular to the line .

Solution:

We have, .

Slope of the line is .

The line which passes through is perpendicular to the line .

Now, the product of the slopes of two perpendicular lines is .

Therefore,

So, its slope is .

Now, the equation of the line which passes through and slope is:

Hence, the equation of the line that contains the point and is perpendicular to the line is .

the co-ordinates of the transformed rectangle are:

d. (0, 0), (0, 3), (-3, 3), (-3, 0)

step-by-step explanation:

from the columns of the given matrix, the co-ordinates of the rectangle before transformation are:

(0, 0), (0, 3), (3, 3), (3, 0)

r =

transformed matrix can be obtained by multiplying the given matrix by r:

columns of the transformed matrix are:

0   0   -3   -3

0   3     3     0

from the columns of the resulted matrix, we can see that the vertices of the transformed triangle are:

(0, 0), (0, 3), (-3, 3), (-3, 0)

the answer is a

step-by-step explanation: