In ΔPQR, the measure of ∠R=90°, the measure of ∠P=38°, and PQ = 62 feet. Find the length of RP to the nearest tenth of a foot.

So it is a right triangle.

R=90°, Q=6° therefore P=84°

If PQ=2.2ft (hypotenuse) when u draw the triangle

Using soh-cah-toa

Base on angle Q=6°

Opposite side is RP

Step-by-step explanation:

Hypotenuse is PQ

sin(6°)=opposite RP/ hypotenuse (22.2ft)

sin%286%29=RP%2F22.2

22.2sin%286%29=RP

RP=2.32

Nearest tenth of a foot RP = 2.3 feet

Hope that helps, I just want to clarify if Q=6° is the correct given. Thank you.

48.9 feet

Step-by-step explanation:

cos P =  Adj / Hyp = X / 62

cos 38 = X / 62

X = 48.8567 = 48.9

m a t h w a y. c o m

step-by-step explanation:

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.