Maria who is 6 feet tall stand 20 feet away from the base of a tree she looks up at the top of the tree at 43° angle of elevation what is the approximate height of the tree rounded to the nearest 10th but

24.7 feet

Step-by-step explanation:

Maria who is 6 feet tall stands 20 feet away from the base of a tree she looks up at the top of the tree at a 43° angle of elevation.

what is the approximate height of the tree rounded to the nearest 10th?

We solve the above question using the Trigonometric function of Tangent

tan θ = Opposite/Adjacent

θ = Angle of elevation

Adjacent = Distance from the base of the tree = 20 feet

Opposite => Height of the tree = x

θ = 43°

tan 43 = x/ 20 feet

x = tan 43 × 20 feet

x = 18.650301723 feet

Approximately = 18.7 feet

We are told in the question that Maria is 6 feet tall

Therefore, the height of the tree = Maria's height + Height

= 6 feet + 18.7 feet

= 24.7 feet

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

2 x 503

step-by-step explanation:

its 1006