Eighteen individuals are scheduled to take a driving test at a particular DMV office on a certain day, eight of whom will be taking the test for the first time. Suppose that six of these individuals are randomly assigned to a particular examiner, and let X be the number among the six who are taking the test for the first time. a. What kind of a distribution does X have (name and values of all parameters)

X has an hypergeometric distribution, with parameters:

Size of the population is N = 18.

Size of the sample is n = 6.

Number of successes n is k = 8.

Step-by-step explanation:

The people are chosen without replacement, which means that the hypergeometric distribution is used.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

Eighteen individuals are scheduled to take a driving test at a particular DMV office on a certain day, eight of whom will be taking the test for the first time.

This means that

We consider a success being a person taking the test for the first time, because X is the number among the six who are taking the test for the first time.

Suppose that six of these individuals are randomly assigned to a particular examiner.

This means that

a. What kind of a distribution does X have (name and values of all parameters)

X has an hypergeometric distribution, with parameters:

Size of the population is N = 18.

Size of the sample is n = 6.

Number of successes n is k = 8.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10