Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with property you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit

a. Quotient property of logarithms, P = log[(d + 1)/d]

b.  log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )