What is the solution set of 2x2 - 3x = 5? 1.) -1,-5/2
2.)-1,5/2
3.) 1,-5/2

i really need this to be answer correctly, the test grade is high

Step-by-step explanation:

we are given a quadratic equation

we have to determine the roots

to do so first bring it to standard form i.e

ax²+bx+c=0

move left hand side expression to right hand side and change its sign:

since we moved left hand side expression to right hand side there's only 0 left to the left hand side

we'll use factoring method to solve the quadratic

first, we need to express the middle term as a sum or subtraction of two different terms

to do so

rewrite -3x as 2x-5x:

now we have two common factors 2x and -5 so

factor them out:

group:

since 2x-5 and x+1 both equal 0

separate the equation as two different equation:

let's work with the first equation:

add 5 to both sides:

divide both sides by 2:

let's work with the second one

cancel 1 from both sides:

hence,

our answer choice is

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction