No Solutions 6−3+4x+1= x + One Solution 6−3+4x+1= x + Infinitely Many Solutions 6−3+4x+1= x +

Complete Question:

Complete each equation, so the statement about its solution is true.

No solutions:

6-3+4x+1= __x + __

One solution:

6-3+4x+1= __x + __

Infinitely many solutions:

6-3+4x+1 = __x + __

--- No solution

--- One solution

--- Infinitely Many solution

Step-by-step explanation:

Solving (a): No solutions

6-3+4x+1= __x + __

Collect like terms

6-3+1+4x= __x + __

4+4x= __x + __

To get no solution, the coefficient of x on both sides must be the same. However, the constant must be different.

So, we can equate the expression to:

Solving (b): One solution

6-3+4x+1= __x + __

This gives (same as (a))

4+4x= __x + __

To get one solution, the coefficient of x on both sides must be different. The constant can have any value.

So, we can equate the expression to:

Solving (c): Infinitely many solutions

6-3+4x+1= __x + __

This gives (same as (a))

4+4x= __x + __

To get infinitely many solutions, both sides of the equation must be equal.

So:

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right