What is an equation of the line that passes through the points (0, 3) and (5, -3)?

Answer (assuming it can be in slope-intercept form):

Step-by-step explanation:

1) First, use the slope formula to find the slope of the line. Substitute the x and y values of the given points into the formula and solve:

So, the slope is .  

2) Now, use the slope-intercept formula to write the equation of the line in slope-intercept form. All you need to do is substitute real values for the and in the formula.

Since represents the slope, substitute for it. Since represents the y-intercept, substitute 3 for it. (Remember, the y-intercept is the point at which the line hits the y-axis. All points on the y-axis have an x-value of 0. Notice how the given point (0,3) has an x-value, too, so it must be the line's y-intercept.) This gives the following equation and

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.