Eric has another cube with edge lengths of 8 inches each He said the edge lengths of the second cube are twice the edge lengths of the first cube,
so the volume of the second cube is twice the volume of the first cube.
Do you agree with Eric? Why or why not?
Type your answer in the box below.

answer ASAP!!

nope

Step-by-step explanation:

Volume of a cube = a^3

1st cube with edge of 8:

V= 8^3

V= 512 cubic inches

2nd cube

V = (2 X 8)^3

V= 4096 cubic inches

If we multiply by 2 the 1st volume it is equal to 1024 cubic inches only, while the volume ogmf the 2nd cube is 4096

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead