Find the x and y for numbers 2 and. 3 thank you

(0, 4 ) and (2, - 4 )

Step-by-step explanation:

(2)

3x + 4y = 16 → (1)

- 3x + 2y = 8 → (2)

Adding (1) and (2) term by term will eliminate the x- term

0 + 6y = 24

6y = 24 ( divide both sides by 6 )

y = 4

Substitute y = 4 into either of the 2 equations and solve for x

Substituting into (1)

3x + 4(4) = 16

3x + 16 = 16 ( subtract 16 from both sides )

3x = 0 , then

x = 0

solution is (0, 4 )

(3)

2x - 4y = 20 → (1)

5x + 4y = - 6 → (2)

Adding (1) and (2) term by term will eliminate the y- term

7x + 0 = 14

7x = 14 ( divide both sides by 7 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (2)

5(2) + 4y = - 6

10 + 4y = - 6 ( subtract 10 from both sides )

4y = - 16 ( divide both sides by 4 )

y = - 4

solution is (2, - 4 )

i believe the answer to be 48

step-by-step explanation:

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6