Select the procedure that can be used to show the converse of the pythagorean theorem using side lengths chosen from 5cm, 9cm, 12cm, and 15cm. A. knowing that 5^2 + 9^2 < 12^2, draw the 5 cm side and the 9 cm side with a right angle between them. The 12 cm side will fit to form a right triangle.
B. Knowing that 9^2 + 12^2 mot equal 15^2, draw the 5 cm side and the 9 cm side with a right angle between them. The 15 cm side will fit to form a right triangle.
C. Knowing that 9^2 + 12^2 = 15^2 , draw any two of the sides with a right angle between them. The third side will fit to form a right triangle.
D. Knowing that 9^2 + 12^2 = 15^2, draw the 9 cm side and the 12 cm side with a right angle between them. The 15 cm side will fit to form a right angle.

Asmall foreign car gete 42 miles per gallon and user 35 gallons on a trip. gasoline costs $1.05 per gallon. what was the cost of gasoline per mile driver?

What set does not contain -3 the set of all real numbers the set of all integers the set of all whole numbers the set of all rational numbers

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.