Can someone help with this?

for A

volume of cuboid =10×8×3=240cm³

volume of cylinder =πr²h=π×4²×7=351.85cm³

so volume of cylinder is greater

for B

surface area of cuboid =2(LB+BH+LH)=2(10×8+8×3+10×3)=268cm²

surface area of cylinder =2πr(r+h)=2×π×4(4+7)=276.36cm²

so surface area of cylinder is greater surface area than of cuboid

56

step-by-step explanation:

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