Y=-x^2+9
What is the vertex
And how do I graph it

You must know the shape of the graph y = x². Its chart is in the form of an upward parabola. The shape of the graph y = -x² is the same except that it is downward. Finally, to draw the shape of the graph y = -x² + 9, we need to move the previously mentioned graph 9 units upwards.

The formula for the vertex length of a parabolic chart is as follows: x= -b/(2a) b=0 , a= 1 → x= 0, y=-(0)²+9=9

vertex: (0,9)

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.