The sum of 3rd and 4th terms of GP is 108 ,The sum of 4th and 6th term of the same GP is 324 ,find common ratio

Complete Question

The sum of 3rd and 4th terms of GP is 108 ,The sum of 4th and 5th term of the same GP is 324 ,find common ratio

3

Step-by-step explanation:

The formula for Number of term of a GP = ar^n-1

The sum of 3rd and 4th terms of GP is 108

ar² + ar³ = 108... Equation 1

ar²(1+ r) = 108 Equation 1

The sum of 4th and 5th term of the same GP is 324 ,

ar³ + ar⁴= 324... Equation 2

ar³ (1 + r) = 324 Equation 2

find common ratio

ar²(1+ r) = 108 Equation 1

ar³ (1 + r) = 324 Equation 2

Solving for r

ar²(1+ r)/ar³ (1 + r) = 108/324

1/r = 1/3

r = 3

Hence, Common ratio = 3

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

what are the statments

step-by-step explanation: