Mathematics, 23.03.2021 16:40, KingKayyy9177
Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs in simplest form.
Answers: 2
![AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}](/tpl/images/1213/9269/47938.png)
![AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}](/tpl/images/1213/9269/24598.png)
(1)
(2)
- Area of the triangle.
- Semiparameter.
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Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units...
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