8. A searchlight is mounted at the front of a helicopter flying 125 m 1 above ground. The angle of depression of the light beam is 70°.
An observer on the ground notices that the beam of light measures 5º.
How wide, to the nearest metre, is d, the spot on the ground?

i dont know this answer im not the best at math but i hope you do get this answer

Step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47