Given that f(x)=3x-6 and h(x)=x^2-3x-4 . Evaluate the following .

f(h(2))

Step-by-step explanation:

The way I understand (remember) the problem is

you want to evaluate h(x)   by substituting 2 in for x's  

then substitute the value for h(2)  into  f(x) to get the answer

evalute f(h(2)) by following the parentheses  

h(x) = x² - 3x - 4        evaluate when x = 2

h(2) = 2² - 3(2) - 4

      =  4  - 6  -  4

h(2)  =  -6              so now -6   is the new x in the f(x) equation

f(x)   = 3x - 6

f(-6) = 3(-6) - 6

      =  -18 - 6

      =  -24

so             f(h(2))  = -24