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Given: \overline{AC} \cong \overline{BD} AC ≅ BD and \angle CAB \cong \angle DBA.∠CAB≅∠DBA. Prove: \triangle ABC \cong \triangle BAD△ABC≅△BAD.
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Given: \overline{AC} \cong \overline{BD} AC ≅ BD and \angle CAB \cong \angle DBA.∠CAB≅∠DBA. Prove: \...
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