Mathematics, 22.03.2021 18:00, stacy99

When solving the system of equations 3x−3y=1 and −2x+4y=2 algebraically, a good first step is to: A. Multiply 3x−3y=1 by 2, and multiply −2x+4y=2 by 3.
B. Multiply 3x−3y=1 by 3, and multiply −2x+4y=2 by −2.
C. Rewrite both equations in slope-intercept form.
D. Add the equations together.

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When solving the system of equations 3x−3y=1 and −2x+4y=2 algebraically, a good first step is to: A...