A poll taken at a school states that 57% of students support extending lunch by 5 minutes. The margin of error is 3%. Write an absolute value inequality to represent the possible percent of students p who support extending lunch.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

idk

step-by-step explanation:

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