You have a hemisphere with a volume of 6. What is the surface area with a sphere with the same diameter. Round to the nearest thousandth.

(the volume of the hemisphere has no units, so i will suppose that it is 6m^3)

For a sphere of radius R, the volume is:

V = (4/3)*pi*R^3

Where pi = 3.14

And a hemisphere is half of a sphere, then the volume of a hemisphere of radius R is:

V = (1/2)*(4/3)*pi*R^3

We know that the volume of the hemisphere is 6 m^3, then we have the equation:

6 m^3 = (1/2)*(4/3)*3.14*R^3

Now we can solve this for R.

6 m^3 = 2.1*R^3

∛(6 m^3/2.1) = R = 1.41 m

The radius of the hemisphere is 1.41m

Now we want to find the surface of a sphere with this radius (if the radius is the same, then the diameter is the same)

For a sphere of radius R, the surface is:

S = 4*pi*R^2

Then the surface of this sphere is:

S = 4*3.14*(1.41 m)^2 = 24.971 m^2

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}